I learned a few things about JavaScript on OpenClassrooms (taking Apprenez à programmer avec JavaScript & Écrivez du JavaScript pour le web courses). I didn't know it then but I was actually looking for DOM manipulation for my Qwixx project. Anyway, I'm refreshing my newbie knowledge by taking FreeCodeCamp JavaScript Algorithms and Data Structures course and here is a recap about arrays.
An array can store multiple pieces of data in a single variable. Each entry is separated by a comma and nested into square brackets. Just like this:
const SANDWICH = ["peanut butter", 1, true, ["bakery", "home-made"]];
An array containing another array is also called a multi-dimensional array. An array can also contain objects.
| "peanut butter" | 1 | true | ["bakery", "home-made"] |
| 0 | 1 | 2 | 3 |
Arrays use zero-based indexing, so the first element in an array has an index of 0. Use square bracket notation to get the data associated to the index. For instance:
console.log(SANDWICH[0]);
const EATEN = SANDWICH[1];
console.log(EATEN);
will print "peanut butter" string and 1 number.
Note that additional pair of brackets refers to the next level of entries inside.
const BOUGHT_IN = SANDWICH[3][0];
console.log(BOUGHT_IN);
will print "bakery".
Use indexOf() method. It returns -1 if the item is not found. For instance:
SANDWICH.indexOf('peanut butter'); // returns 0
SANDWICH.indexOf('butter'); // returns -1
Use spread operator (...). For instance (from FreeCodeCamp):
const arr = [6, 89, 3, 45];
const maximus = Math.max(...arr); // maximus has the value of 89
Use a for loop. It looks like this:
let array = [1, 2, 3]
for (let i = 0; i < array.length; i++) {
console.log(array[i])
} // logs 1, 2, 3, each on its own line
Even if an array is defined as a const its entries are mutable. From our example,
SANDWICH[0] = "houmus";
SANDWICH now has the value
["houmus", 1, true, ["bakery", "home-made"]];
Use push() method. It takes one or more parameters and "pushes" them onto the end of an array. For instance:
const arr = [1, 2, 3];
arr.push(4);
arr now has the value [1, 2, 3, 4]
Use unshift() method. For instance:
const arr = [1, 2, 3];
arr.unshift(0);
arr now has the value [0, 1, 2, 3]
Use splice() method.
First argument: the index at which to begin deleting elements
Second argument (optional): the number of elements to be deleted
Third argument (optional): items to insert starting at that same index, searated by a comma
For instance (example from FreeCodeCamp):
const numbers = [10, 11, 12, 12, 15];
const startIndex = 3;
const amountToDelete = 1;
numbers.splice(startIndex, amountToDelete, 13, 14);
console.log(numbers); // returns [ 10, 11, 12, 13, 14, 15 ]
User spread operator (...). For instance (example from FreeCodeCamp):
let arrayToAppend = ['sage', 'rosemary', 'parsley', 'thyme'];
let mainArray = ['basil', 'cilantro', ...arrayToAppend, 'coriander'];
mainArray now has the value ['basil', 'cilantro', 'sage', 'rosemary', 'parsley', 'thyme', 'coriander']
Use pop() method. For instance:
const arr = [1, 2, 3];
arr.pop();
arr now has the value [1, 2]
Use shift() method. For instance:
const arr = [1, 2, 3];
arr.shift();
arr now has the value [2, 3]
Note: removed data can be returned if assigned to a variable. For instance:
const arr = [1, 2, 3];
let removedNumber = arr.pop();
let one = arr.shift();
removedNumber has the number 3 as a value and one, 1
You can also use splice() method!
First argument: the index at which to begin deleting elements
Second argument (optional): the number of elements to be deleted
For instance (from FreeCodeCamp):
let array = ['today', 'was', 'not', 'so', 'great'];
array.splice(2, 2); // array now has the value ['today', 'was', 'great']
Here we remove 2 elements, beginning with the third element (at index 2). array would have the value
Note: removed data can be returned if assigned to a variable.
I realized it was not working like classic variables like these:
let a = "first variable"; // a contains "first variable" string
let b = a; // a and b contain "first variable" string
b = "second variable"; // a contains "first variable" and b "second variable" string
let array1 = [1, 2, 3]; // array1 contains [1, 2, 3] array
let array2 = array1; // array1 and array2 contain [1, 2, 3] array
array2.unshift(0); // array1 and array2 contain [0, 1, 2, 3] array
Here, array2 behaves just like another pointer to the same object. Modifying array2 will modify array1 and inversely. So how can we copy an array? Here are several methods:
For instance:
let originalArray = ['great', 'awesome', 'super', 'wonderful'];
let copiedArray = [...originalArray];
originalArray remains unchanged and copiedArray has the same elements as originalArray.
With slice() method, we can copy or extract a given number of elements to a new array, leaving the original array unchanged. It takes 2 parameters:
First argument: the index at which to begin extraction
Second argument (optional): the index at which to stop extraction (not included)
For instance (example from FreeCodeCamp):
let weatherConditions = ['rain', 'snow', 'sleet', 'hail', 'clear'];
let todaysWeather = weatherConditions.slice(1, 3); // todaysWeather is ['snow', 'sleet']